If the sum of the distances of a point from two perpendicular lines in a plane is 1 , then its locus is

Let $P=(h, k)$ be any point in the locus let $x, y$-axes be two perpendicular lines $\therefore$ Distance from $P(h, k)$ to $X$-axis $=1$ (given) $$ |k|=1 $$ Distance from $P(h, k)$ to $Y$-axis $=1 \Rightarrow|h|=1$ According to the question, $|h|+|k|=1$ $\therefore$ The locus of point $(h, k)$ is $|x|+|y|=1$ $\therefore$ It is a square Hence, option (2) is correct