Q19 / 160 · AP EAMCET 2018 (24 Apr Shift 1) · Chemistry
If the side length of a face centered unit cell of a metal is $400 \mathrm{pm}$, approximate radius of the metal in pm is $(\sqrt{2}=1.414)$
- A14.14
- B35.3
- C176.7
- Correct answerD141.4
Solution
Edge/side length of a fcc $=400 \mathrm{pm}$
$\because$ For fcc
$$
\begin{aligned}
r & =\frac{a}{2 \sqrt{2}} \\
\therefore \quad r & =\frac{400}{2 \times 1.414}=141.4 \mathrm{pm}
\end{aligned}
$$
Hence, the correct answer is option: 'D'.