If the series limit wavelength of the Lyman series of hydrogen atom is $912\mathrm{Å},$ then the series limit wavelength of the Balmer series of the hydrogen atom is

• A

  $912\mathrm{Å}$
• B

  $1824\mathrm{Å}$
• Correct answer
  C

  $3648\mathrm{Å}$
• D

  $456\mathrm{Å}$

Hence, the correct answer is option: 'C'.