Q79 / 160 · AP EAMCET 2025 (22 MAY SHIFT 1) · Mathematics

If the probability distribution of a random variable $X$ is as follows, then $P(x \leq 2)=$
$x_i$01234
$P\left(X = x_i\right)$3K5K$3k^2$$4k^2 + k$$3k^2$

  • A
    $\frac{14}{25}$
  • B
    $\frac{23}{32}$
  • C
    $\frac{41}{49}$
  • Correct answer
    D
    $\frac{83}{100}$

Hence, the correct answer is option: 'D'.

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