Q79 / 160 · AP EAMCET 2025 (22 MAY SHIFT 1) · Mathematics
If the probability distribution of a random variable $X$ is as follows, then $P(x \leq 2)=$ $x_i$ 0 1 2 3 4 $P\left(X = x_i\right)$ 3K 5K $3k^2$ $4k^2 + k$ $3k^2$
| $x_i$ | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| $P\left(X = x_i\right)$ | 3K | 5K | $3k^2$ | $4k^2 + k$ | $3k^2$ |
- A$\frac{14}{25}$
- B$\frac{23}{32}$
- C$\frac{41}{49}$
- Correct answerD$\frac{83}{100}$
Hence, the correct answer is option: 'D'.