Q104 / 160 · AP EAMCET 2014 · Mathematics
If the point $P(1,3)$ undergoes the following transformations successively.
(i) Reflection with respect to the line $y=x$.
(ii) Translation through 3 units along the positive direction of the $X$-axis.
(iii) Rotation through an angle of $\frac{\pi}{6}$ about the origin in the clockwise direction.
Then, the final position of the point $P$ is
- Correct answerA$\left(\frac{6 \sqrt{3}+1}{2}, \frac{\sqrt{3}-6}{2}\right)$
- B$\left(\frac{\sqrt{7}}{2}, \frac{-5}{\sqrt{2}}\right)$
- C$\left(\frac{6+\sqrt{3}}{2}, \frac{1-6 \sqrt{3}}{2}\right)$
- D$\left(\frac{6+\sqrt{3}-1}{2}, \frac{6+\sqrt{3}}{2}\right)$
Solution
The reflection of the point $P(1,3)$ about the line $y=x$ is $Q(3,1)$

After translation through a distance 3 units along the positive direction of $X$-axis at the point whose coordinate are $R(6,1)$. After rotation through an angle of $\frac{\pi}{6}$ about the origin in the clockwise direction, then $R$ goes to whose coordinates are $$ R^{\prime}\left(\frac{6 \sqrt{3}+1}{2}, \frac{\sqrt{3}-6}{2}\right) $$

After translation through a distance 3 units along the positive direction of $X$-axis at the point whose coordinate are $R(6,1)$. After rotation through an angle of $\frac{\pi}{6}$ about the origin in the clockwise direction, then $R$ goes to whose coordinates are $$ R^{\prime}\left(\frac{6 \sqrt{3}+1}{2}, \frac{\sqrt{3}-6}{2}\right) $$
Hence, the correct answer is option: 'A'.