Q153 / 160 · TS EAMCET 2024 (10 May Shift 1) · Physics

If the peak value of the magnetic field of an electromagnetic wave is $30 \times 10^{-9} \mathrm{~T}$, then the peak value of the electric. field is

  • A
    $3 \mathrm{Vm}^{-1}$
  • B
    $12 \mathrm{Vm}^{-1}$
  • C
    $6 \mathrm{Vm}^{-1}$
  • Correct answer
    D
    $9 \mathrm{Vm}^{-1}$

Solution

For EM wave, $\mathrm{B}_{\mathrm{o}}=30 \times 10^{-9} \mathrm{~T}, \mathrm{C}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ $\therefore$ Peak value of electric field is $E_0=C B_0={ }^{\prime} 3 \times 10^8 \times 30 \times 10^{-9}=9 \mathrm{Vm}^{-1}$

Hence, the correct answer is option: 'D'.

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