If the osmotic pressure of cane sugar solution is 2.46 ~atm at 27^° C , then what is the concentration (in mol L^-1 ) of the solution ( .R=0.0821 ~L ~atm ~mol^-1 ~K^-1 )

Correct answer: (A) 0.1. π=CRT ⇒ C=(π)/RT=2.46/(0.082 ×(27+273)) =0.1 ~mol ~L^-1 .

Q21 / 160 · AP EAMCET 2023 (17 May Shift 2) · Chemistry

If the osmotic pressure of cane sugar solution is $2.46 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$, then what is the concentration (in $\mathrm{mol} \mathrm{L}^{-1}$ ) of the solution ( $\left.\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)$

$\pi=\mathrm{CRT} \Rightarrow \mathrm{C}=\frac{\pi}{\mathrm{RT}}=\frac{2.46}{0.082 \times(27+273)}$ $=0.1 \mathrm{~mol} \mathrm{~L}^{-1}$.

Hence, the correct answer is option: 'A'.