Q80 / 160 · TS EAMCET 2025 (03 May Shift 2) · Mathematics
If the mean and variance of a binomial distribution are $\frac{4}{3}$ and $\frac{10}{9}$ respectively, then $\mathrm{P}(\mathrm{X} \geq 6)=$
- A$\frac{41}{6^8}$
- Correct answerB$\frac{741}{6^8}$
- C$1-\frac{741}{6^8}$
- D$1-\frac{41}{6^8}$
Hence, the correct answer is option: 'B'.