Q33 / 160 · AP EAMCET 2003 · Chemistry

If the mass defect of a nuclide is $3.32 \times 10^{-26} \mathrm{~g}$, its binding energy is $\mathrm{MeV}$

  • A
    9.31
  • Correct answer
    B
    18.62
  • C
    27.93
  • D
    37.24

Solution

Mass defect $=3.32 \times 10^{-26} \mathrm{~g}$ $=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \mathrm{amu}$ Binding energy $=$ Mass defect $\times 931 \mathrm{MeV}$ $=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \times 931=18.62 \mathrm{MeV}$

Hence, the correct answer is option: 'B'.

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