If the lines $x+y-2=0,3 x-4 y+1=0$ and $5 x+k y-7=0$ are concurrent at $(\alpha, \beta)$, then equation of the line concurrent with the given lines and perpendicular to $\mathrm{kx}+\mathrm{y}-\mathrm{k}=0$ is

• A

  $x-3 y=-2$
• B

  $x+4 y=5$
• C

  $x+6 y=7$
• Correct answer
  D

  $x-2 y=-1$

Hence, the correct answer is option: 'D'.