If the line (x-4)/1=(y-2)/1=(z-k)/2 lies in the plane 2 x-4 y+z=7 , then the value of k is

Correct answer: (C) 7. The point (4,2, k) on the line also lies on the plane 2 x-4 y+z=7 So, 8-8+k=7 ⇒ k=7

Q76 / 125 · BITSAT 2009 · Mathematics

If the line \(\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}\) lies in the plane \(2 x-4 y+z=7\), then the value of \(k\) is

The point \((4,2, k)\) on the line also lies on the plane \(2 x-4 y+z=7\) So, \(8-8+\mathrm{k}=7 \Rightarrow \mathrm{k}=7\)

Hence, the correct answer is option: 'C'.