Q74 / 160 · TS EAMCET 2018 (05 May Shift 2) · Mathematics
If the line $\mathbf{r}=\mathbf{a}+t \mathbf{b}$ is parallel to the plane $\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}$, then
- A$[\mathrm{abc}]=0$
- B$[\mathrm{bcd}]=0$
- C$[\mathrm{cde}]=0$
- Correct answerD$[\mathrm{bde}]=0$
Solution
We have,
Line $\mathbf{r}=\mathbf{a}+\mathbf{l} \mathbf{b}$ is paralleI to the plane
$\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}$
$\therefore$ Normal vector of plane are $(\mathrm{d} \times \mathbf{e})$.
Since, line and plane are parallel.
Hence, the correct answer is option: 'D'.