Q83 / 160 · AP EAMCET 2021 (24 Aug Shift 2) · Mathematics

If the line $p x-q y=r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$, then the value of $(a+b)$ is equal to

  • A
    $\frac{r(q+p)}{p q}$
  • Correct answer
    B
    $\frac{r(q-p)}{p q}$
  • C
    $\frac{r(p-q)}{p q}$
  • D
    $\frac{r(p-q)}{p+q}$

Solution

We have, $p x-q y=r$ intersect the coordinates axes at $(a, 0)$ and $(0, b)$. $\therefore \quad p a=r \Rightarrow a=\frac{r}{p}$ $0-b q=r \Rightarrow b=\frac{-r}{q}$ $\therefore \quad a+b=\frac{r}{p}-\frac{r}{q}=\frac{r(q-p)}{p q}$

Hence, the correct answer is option: 'B'.

Relevant Questions