Q190 / 225 · JEE Main 2005 · Physics
If the kinetic energy of a free electron doubles. Its deBroglie wavelength changes by the factor
- A$\frac{1}{2}$
- B2
- Correct answerC$\frac{1}{\sqrt{2}}$
- D$\sqrt{2}$
Solution
$\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{Km}}}$
Hence, the correct answer is option: 'C'.