Q116 / 160 · WBJEE 2011 · Mathematics
If the function
\(f(x)= \begin{cases}\frac{x^2-(A+2) x+A}{x-2} & \text { for } x \neq 2 \\ 2 & \text { for } x=2\end{cases}\)
is continuous at \(x=2\), then
- Correct answerA\(\mathrm{A}=0\)
- B\(\mathrm{A}=1\)
- C\(\mathrm{A}=-1\)
- D\(\mathrm{A}=2\)
Solution
Hints: \(\frac{4-(A+2) 2+A}{0}=\frac{-A}{0}\)
Put \(\mathrm{A}=0\).
Hence, the correct answer is option: 'A'.