If the equation of the circumcircle of the triangle formed by the lines $\mathrm{L}_1 \equiv x+y=0$, $\mathrm{L}_2 \equiv 2 x+y-1=0, \mathrm{~L}_3 \equiv x-3 y+2=0$ is $\lambda_1 \mathrm{~L}_1 \mathrm{~L}_2+\lambda_2 \mathrm{~L}_2 \mathrm{~L}_3+\lambda_3 \mathrm{~L}_3 \mathrm{~L}_1=0$, then $\frac{7 \lambda_1}{\lambda_2}+\frac{\lambda_3}{\lambda_1}=$

• A

  $1$
• B

  $2$
• Correct answer
  C

  $3$
• D

  $4$

Hence, the correct answer is option: 'C'.