If the equation of the circle lying in the first quadrant, touching both the coordinate axes and the line $\frac{x}{3}+\frac{y}{4}=1$ is $(x-c)^2+(y-c)^2=c^2$, then $c=$

• A

  1 or 4
• B

  2 or 3
• Correct answer
  C

  1 or 6
• D

  2 or 5

Hence, the correct answer is option: 'C'.