If the electric potential at any point $\left(x, y, z\right) \mathrm{m}$ in space is given by $V=3x^2$ volt. The electric field at the point $\left(1, 0, 3\right) \mathrm{m}$ will be :

• A

  $3 {\mathrm{Vm}}^{-1}$, directed along positive $x$-axis.
• B

  $3 {\mathrm{Vm}}^{-1}$, directed along negative $x$-axis.
• Correct answer
  C

  $6 {\mathrm{Vm}}^{-1}$, directed along negative $x$-axis.
• D

  $6 {\mathrm{Vm}}^{-1}$, directed along positive $x$-axis.

Hence, the correct answer is option: 'C'.