Q29 / 160 · AP EAMCET 2021 (24 Aug Shift 1) · Chemistry

If the conductivity of a $0.5 \mathrm{M} \mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $0.024 \mathrm{~S} \mathrm{~cm}^{-1}$, then the molar conductivity of the solution would be $\mathrm{Scm}^2 \mathrm{~mol}^{-1}$.

  • A
    150
  • Correct answer
    B
    48
  • C
    24
  • D
    121.4

Solution

Electrolytic conductivity, $\kappa=0.024 \mathrm{~S} \mathrm{~cm}^{-1}$ Molar concentration $=0.5 \mathrm{M}$ $$ \begin{aligned} \Lambda_{\mathrm{m}}^0(\text { Molar conductivity }) & =\frac{\kappa \times 1000}{M} \\ =\frac{0.024 \times 1000}{0.5} & =48 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1} . \end{aligned} $$

Hence, the correct answer is option: 'B'.

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