If the coefficient of x^6 in the expansion of 2+x^33+x^25+x^3 is K, then the value of K/100 is

Question

MARKS Content Team · Accepted Answer

Correct answer: 3.12. x+2^3x+3^2x+5^3=x^8+x^72+2+2+3+3+5+5+5+x^6K+....... Clearly, K is equal to the sum taken two at a time of 2,2,2,3,3,5,5,5. ⇒K=(2+2+2+3+3+5+5+5^2-2^2+2^2+2^2+3^2+3^2+5^2+5^2+5^2)/2 =(27^2-4+4+4+9+9+25+25+25)/2 =(729-105)/2=624/2=312 ⇒K/100=3.12

If the coefficient of $x^{6}$ in the expansion of ${(2 + x)}^{3} {(3 + x)}^{2} {(5 + x)}^{3}$ is $K,$ then the value of $\frac{K}{100}$ is

Solution

More Binomial Theorem Questions

If the coefficient of x6 in the expansion of 2+x33+x25+x3 is K, then the value of K100 is

Solution

More Binomial Theorem Questions

If the coefficient of $x^{6}$ in the expansion of ${(2 + x)}^{3} {(3 + x)}^{2} {(5 + x)}^{3}$ is $K,$ then the value of $\frac{K}{100}$ is