Q64 / 110 · VITEEE 2022 · Mathematics
If the binary operation \(*\) is defined on the set \(\mathrm{Q}^{+}\) of all positive rational numbers by \(\mathrm{a} * \mathrm{~b}=\frac{\mathrm{ab}}{4}\).
Then \(3 *\left(\frac{1}{5} * \frac{1}{2}\right)\) is equal to
- Correct answerA\(\frac{3}{160}\)
- B\(\frac{5}{160}\)
- C\(\frac{3}{10}\)
- D\(\frac{3}{40}\)
Solution
Given that \(\mathrm{a} * \mathrm{~b}=\frac{\mathrm{ab}}{4} \forall \mathrm{a}, \mathrm{b} \in \mathrm{Q}^{+}\)
\(\begin{aligned}
\therefore \quad 3 *\left(\frac{1}{5} * \frac{1}{2}\right) & =3 *\left\{\frac{\frac{1}{5} \times \frac{1}{2}}{4}\right\}=3 * \frac{1}{40}=\frac{\left(3 \times \frac{1}{40}\right)}{4} \\
& =\frac{3}{160}
\end{aligned}\)
Hence, the correct answer is option: 'A'.