Q10 / 150 · MHT CET 2026 (18 April Shift 2) · Chemistry

If standard reduction potential of four electrodes A, B, C, D are $+2.5\,\text{V}, +3.0\,\text{V}, -2.0\,\text{V}$ and $-1.5\,\text{V}$ respectively. When is the standard emf of cell maximum?

  • A
    'A' is anode and 'B' is cathode
  • B
    'B' is anode and 'D' is cathode
  • Correct answer
    C
    'C' is anode and 'B' is cathode
  • D
    'B' is anode and 'C' is cathode

Solution

The standard emf of a cell is given by $E^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}}$.

To obtain the maximum standard emf, the cathode must have the highest standard reduction potential and the anode must have the lowest standard reduction potential.

Given standard reduction potentials are:
$E^{\circ}_{\text{A}} = +2.5\text{ V}$
$E^{\circ}_{\text{B}} = +3.0\text{ V}$
$E^{\circ}_{\text{C}} = -2.0\text{ V}$
$E^{\circ}_{\text{D}} = -1.5\text{ V}$

The highest reduction potential is for electrode B ($+3.0\text{ V}$), so B should act as the cathode.

The lowest reduction potential is for electrode C ($-2.0\text{ V}$), so C should act as the anode.

Maximum $E^{\circ}_{\text{cell}} = 3.0 - (-2.0) = 5.0\text{ V}$.

Thus, 'C' is the anode and 'B' is the cathode.

Answer: 'C' is anode and 'B' is cathode

Hence, the correct answer is option: 'C'.

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