Q117 / 150 · MHT CET 2019 (02 May Shift 1) · Physics

If radius of the solid sphere is doubled by keeping its mass constant, the ratio of their moment of inertia about any of its diameter is

A
$1 : 8$
B
$2 : 5$
C
$2 : 3$
Correct answer
D
$1 : 4$

Solution

\frac{I_{1}}{I_{2}} = \frac{\frac{2}{5} m R^{2}}{\frac{2}{5} m {(2 R)}^{2}} = \frac{1}{4}

Hence, the correct answer is option: 'D'.

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