If radius of the ${}_{13}{}^{27}\mathrm{A}\mathrm{l}$ nucleus is taken to be $R_{\mathrm{A}\mathrm{l}}$ then the radius of ${}_{53}{}^{125}\mathrm{T}\mathrm{e}$ nucleus is nearly

• A

  ${\left(\frac{53}{13}\right)}^{\frac{1}{3}}\mathrm{ }{R}_{\mathrm{A}\mathrm{l}}$
• Correct answer
  B

  $\frac{5}{3}{R}_{\mathrm{A}\mathrm{l}}$
• C

  $\frac{3}{5}{R}_{\mathrm{A}\mathrm{l}}$
• D

  ${\left(\frac{13}{53}\right)}^{\frac{1}{3}}\mathrm{ }{R}_{\mathrm{A}\mathrm{l}}$

Hence, the correct answer is option: 'B'.