Q52 / 150 · MHT CET 2019 (02 May Shift 1) · Mathematics

If Px1,y1 is a point on the hyperbola x2-y2=a2, then SP.S'P= ________

  • A
    x12-y12a2
  • B
    x12+y12a2
  • C
    x12-y12
  • Correct answer
    D
    x12+y12

Solution

Given Hyperbola x2-y2=a2 is
Rectangular hyperbola, its e=2
Then S2a,0 and S'-2a,0
Also S'P=2x1+a and SP =2x1-a
Then SPS'P=2x12-a2∵x12-y12=a2
Hence, SPS'P=x12+y12

Hence, the correct answer is option: 'D'.

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