Q89 / 225 · JEE Main 2004 · Mathematics

If one root of the equation $x^2+p x+12=0$ is 4 , while the equation $x^2+p x+q=0$ has equal roots, then the value of ' $q$ ' is

  • Correct answer
    A
    $\frac{49}{4}$
  • B
    4
  • C
    3
  • D
    12

Solution

Since 4 is one of the root of $x^2+p x+12=0 \Rightarrow 16+4 p+12=0 \Rightarrow p=-7$ and equation $x^2+p x+q=0$ has equal roots $$ \Rightarrow D=49-4 q=0 \Rightarrow q=\frac{49}{4} $$

Hence, the correct answer is option: 'A'.

Relevant Questions