Q71 / 120 · JEE Main 2007 · Mathematics

If one of the lines of $m y^2+\left(1-m^2\right) x y-m x^2=0$ is a bisector of the angle between the lines $x y=0$, then $m$ is

  • A
    $-1 / 2$
  • B
    $-2$
  • Correct answer
    C
    $1$
  • D
    $2$

Solution

Equation of bisectors of lines $x y=0$ are $y=\pm x$ put $y=\pm x$ in $m y^2+\left(1-m^2\right) x y-m x^2=0$, we get $\left(1-m^2\right) x^2=0$ $\Rightarrow m=\pm 1$.

Hence, the correct answer is option: 'C'.

More Straight Lines Questions