If one of the diameters of the circle, given by the equation, x^2+y^2-4x+6y-12=0, is a chord of a circle S, whose centre is at -3, 2, then the radius…

Question

If one of the diameters of the circle, given by the equation, x^2+y^2-4x+6y-12=0, is a chord of a circle S, whose centre is at -3, 2, then the radius of S is

MARKS Content Team · Accepted Answer

Correct answer: (D) 5√3. The centre of the given circle x^2+y^2-4x+6y-12=0 is 2, -3 and the radius is 5. ​​​​​​​ The distance between the centres 5√2 and radius is 5. The triangle OPQ is a right angled triangle OQ= √(52^2+5^2)= √(53^2)=5√3 Hence answer is 5√3

If one of the diameters of the circle, given by the equation, $x^{2} + y^{2} - 4 x + 6 y - 12 = 0,$ is a chord of a circle $S$ , whose centre is at $(- 3, 2)$ , then the radius of $S$ is

Solution

Relevant Questions

If one of the diameters of the circle, given by the equation, x2+y2-4x+6y-12=0, is a chord of a circle S, whose centre is at -3, 2, then the radius of S is

Solution

Relevant Questions

If one of the diameters of the circle, given by the equation, $x^{2} + y^{2} - 4 x + 6 y - 12 = 0,$ is a chord of a circle $S$ , whose centre is at $(- 3, 2)$ , then the radius of $S$ is