Q123 / 160 · AP EAMCET 2011 · Physics

If $200 \mathrm{MeV}$ of energy is released in the fission of one nucleus of ${ }_{92}^{236} \mathrm{U}$, the number of nuclei that must undergo fission to release an energy of $1000 \mathrm{~J}$ is

  • Correct answer
    A
    $3.125 \times 10^{13}$
  • B
    $6.25 \times 10^{13}$
  • C
    $12.5 \times 10^{13}$
  • D
    $3.125 \times 10^{14}$

Solution

Energy released in the fission of one nucleus $\begin{aligned} & =200 \mathrm{MeV} \\ & =200 \times 1.6 \times 10^{-13} \mathrm{~J} \\ & =3.2 \times 10^{-11} \mathrm{~J} \end{aligned}$ Energy to be released $=1000 \mathrm{~J}$ $3.2 \times 10^{-11} \mathrm{~J}$ energy is released due to number of nucleus fissioned $=1$ $\therefore 1000 \mathrm{~J}$ energy is released due to number of nucleus fissioned $\begin{aligned} & =\frac{1 \times 1000}{3.2 \times 10^{-11}} \\ & =3.125 \times 10^{13} \text { nucleus } \end{aligned}$

Hence, the correct answer is option: 'A'.

Relevant Questions