Q116 / 180 · AIIMS 2019 (26 May) · Physics

If maximum energy is stored in capacitor at $t=0$, then find the time after which current in the circuit will be maximum Figure

  • A
    $\frac{\pi}{2} \mathrm{~ms}$
  • Correct answer
    B
    $\frac{\pi}{4} \mathrm{~ms}$
  • C
    $\pi \mathrm{ms}$
  • D
    $2 \mathrm{~ms}$

Solution

In $L-C$ oscillations, total time in one complete cycle is, $T=2 \pi \sqrt{L C}$ $\begin{aligned} & T=2 \pi \sqrt{25 \times 10^{-3} \times 10 \times 10^{-6}} \\ & \Rightarrow T=2 \pi \sqrt{25 \times 10^{-8}} \\ & =\pi \times 10^{-3} \mathrm{sec}\end{aligned}$ After time $T / 4$ capacitor is fully discharged and current in circuit will be maximum, then $\frac{T}{4}=\frac{\pi \times 10^{-3}}{4}=\frac{\pi}{4} \mathrm{~ms}$

Hence, the correct answer is option: 'B'.

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