If ${\log }_{10}\left(\frac{x^3-y^3}{x^3+y^3}\right)=2$, then $\frac{dy}{dx}=$

• A

  $\frac{x}{y}$
• B

  $-\frac{y}{x}$
• C

  $-\frac{x}{y}$
• Correct answer
  D

  $\frac{y}{x}$

Hence, the correct answer is option: 'D'.