If log_10⁡(x^2-y^2)/(x^2+y^2)=2, then dy/dx= _______

Question

MARKS Content Team · Accepted Answer

Correct answer: (A) -99x/101y. Given, log_10⁡ (x^2-y^2)/(x^2+y^2)=2 ⇒ (x^2-y^2)/(x^2+y^2)=100 ⇒ (x^2-y^2-100x^2-100y^2)/(x^2+y^2)=0 ⇒ (-99x^2-101y^2)/(x^2+y^2)=0 ⇒ 99x^2+101y^2=0 ⇒ 2×99x+2×101 ydy/dx=0 ⇒ dy/dx=-99x/101y

If $\log_{10} (\frac{x^{2} - y^{2}}{x^{2} + y^{2}}) = 2,$ then $\frac{d y}{d x} =$ _______

Solution

Relevant Questions

If log10⁡x2-y2x2+y2=2, then dydx= _______

Solution

Relevant Questions

If $\log_{10} (\frac{x^{2} - y^{2}}{x^{2} + y^{2}}) = 2,$ then $\frac{d y}{d x} =$ _______