If x-1 is x^5-4 x^3+2 x^2-3 x+k=0 , then k is a

Q62 / 180 · KCET 2012 · Mathematics

If $x-1 \quad$ is $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$, then $k$ is $a$

Correct answer
A
4
B
$-4$
C
2
D
3

Solution

Since, $x-1$ is a factor of $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$ Therefore, $x=1$ must satisfy the given equation. $\therefore \quad(1)^{5}-4(1)^{3}+2(1)^{2}-3(1)+\mathrm{k}=0$ $1-4+2-3+k=0$ $\Rightarrow \quad \mathrm{k}=4$

Hence, the correct answer is option: 'A'.

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