Q166 / 180 · KCET 2012 · Physics

If $\mathrm{n}$ is the orbit number of the electron in a hydrogen atom, the correct statement among the following is

  • A
    electron energy varies as $\mathrm{n}^{2}$
  • Correct answer
    B
    electron energy increases as $\mathrm{n}$ increases
  • C
    hydrogen emits infrared rays for the electron transition from $\mathrm{n}=\infty$ to $\mathrm{n}=1$
  • D
    electron energy is zero for $n=1$

Solution

$$ \mathrm{E}=-\frac{13.6}{\mathrm{n}^{2}} \mathrm{eV} $$ Hence, electron energy increases as $n$ increases.

Hence, the correct answer is option: 'B'.

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