Q157 / 160 · AP EAMCET 2017 (26 Apr Shift 2) · Physics
If $\Delta \lambda_L$ is the difference between shortest and longest wavelengths of Lymann series and $\Delta \lambda_B$ is the difference between shortest and longest wavelengths of Balmer series, then $\frac{\Delta \lambda_B}{\Delta \lambda_L}=$
- A2.4
- B4.8
- C7.2
- Correct answerD9.6
Hence, the correct answer is option: 'D'.