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Q157 / 160 · AP EAMCET 2017 (26 Apr Shift 2) · Physics

Q67 / 75 · AP EAMCET 2017 (26 Apr Shift 2) · Physics · Atomic Physics · Atomic Spectrum

If $\Delta \lambda_L$ is the difference between shortest and longest wavelengths of Lymann series and $\Delta \lambda_B$ is the difference between shortest and longest wavelengths of Balmer series, then $\frac{\Delta \lambda_B}{\Delta \lambda_L}=$

  • A
    2.4
  • B
    4.8
  • C
    7.2
  • Correct answer
    D
    9.6

Hence, the correct answer is option: 'D'.

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