If $\theta$ is the angle subtended by a latus rectum at the centre of the hyperbola having eccentricity $\frac{2}{\sqrt{7}-\sqrt{3}}$, then $\sin \theta=$

• Correct answer
  A

  $\frac{1}{2} \tan \frac{\theta}{2}$
• B

  $2 \cos \frac{\theta}{2}$
• C

  $\frac{1}{\sin \frac{\theta}{2}+\cos \frac{\theta}{2}}$
• D

  $1-\cos \frac{\theta}{2}$

Hence, the correct answer is option: 'A'.