If $\theta$ is in the third quadrant, then $\sqrt{4 \sin ^4 \theta+\sin ^2 2 \theta}+4 \cos ^2\left(\frac{\pi}{4}-\frac{\theta}{2}\right)=$

• A

  $1+2 \sin \theta$
• Correct answer
  B

  2
• C

  1
• D

  $2+4 \sin \theta$

Hence, the correct answer is option: 'B'.