Q164 / 270 · NDA 2017 (Phase 2) · Mathematics
If $A$ is a square matrix, then the value of $\operatorname{adj} A^T-(\operatorname{adj} A)^T$ is equal to
- AA
- B$2|\mathrm{~A}| \mathrm{I}$, where I is the identity matrix
- Correct answerCnull matrix whose order is same as that of A
- Dunit matrix whose order is same as that of A
Solution
We know, $\operatorname{Adj} A^{\mathrm{T}}=(\operatorname{adj} A)^{\mathrm{T}}$
$\therefore \operatorname{adj} \mathrm{A}^{\mathrm{T}}-(\operatorname{adj} \mathrm{A})^{\mathrm{T}}=\operatorname{adj} \mathrm{A}^{\mathrm{T}}-\operatorname{adj} \mathrm{A}^{\mathrm{T}}=0$.
Hence, the correct answer is option: 'C'.