Q94 / 160 · TS EAMCET 2020 (14 Sep Shift 2) · Mathematics

If $P Q$ is a focal chord of the parabola $y^2=4 x$ with focus $S$ and $P=(4,4)$, then $S Q=$

  • A
    2
  • Correct answer
    B
    $\frac{5}{4}$
  • C
    5
  • D
    $\frac{3}{2}$

Solution

$P Q$ is focal chord of parabola $y^2=4 x$ focus $S(1,0)$ and $P(4,4)$ We know that, Length of Semi-latus rectum is Harmonic mean of $P S$ and $S Q$ Figure
$\begin{aligned} \therefore \quad \frac{1}{P S}+\frac{1}{S Q} & =1 \Rightarrow \frac{1}{S Q}=1-\frac{1}{P S} \\ \frac{1}{S Q} & =1-\frac{1}{\sqrt{9+16}}=1-\frac{1}{5}=\frac{4}{5} \Rightarrow S Q=\frac{5}{4}\end{aligned}$

Hence, the correct answer is option: 'B'.

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