Q55 / 160 · TS EAMCET 2004 · Mathematics
If $(x-2)$ is a common factor of the expressions $x^2+a x+b$ and $x^2+c x+d$, then $\frac{b-d}{c-a}$ is equal to
- A$-2$
- B$-1$
- C$1$
- Correct answerD$2$
Solution
Since, $(x-2)$ is a common factor of the expressions $x^2+a x+b$ and $x^2+c x+d$

$\begin{array}{rlrl}\Rightarrow & 2 a+b =2 c+d \\ \Rightarrow & b-d =2(c-a) \\ \Rightarrow & \frac{b-d}{c-a} =2\end{array}$

$\begin{array}{rlrl}\Rightarrow & 2 a+b =2 c+d \\ \Rightarrow & b-d =2(c-a) \\ \Rightarrow & \frac{b-d}{c-a} =2\end{array}$
Hence, the correct answer is option: 'D'.