Q198 / 225 · JEE Main 2002 · Physics

If in the circuit, power dissipation is $150 \mathrm{~W}$, then $\mathrm{R}$ is Figure

  • A
    $2 \Omega$
  • Correct answer
    B
    $6 \Omega$
  • C
    $5 \Omega$
  • D
    $4 \Omega$

Solution

$W=\frac{V^2}{R_{\text {net }}} ; 150=\frac{(15)^2}{R}+\frac{(15)^2}{2} \Rightarrow R=6 \Omega$

Hence, the correct answer is option: 'B'.

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