Q116 / 180 · JIPMER 2019 · Physics

If frequency of a photon is $6 \times 10^{14} \mathrm{~Hz}$, then find its wavelength. [Take, speed of light, $\mathrm{c}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ ]

  • A
    $500 Å$
  • Correct answer
    B
    $500 nm$
  • C
    $200 Å$
  • D
    $200 nm$

Solution

Given, Frequency of photon $(v)=6 \times 10^{14} \mathrm{~Hz}$ Speed of light $(\mathrm{c})=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ $\therefore$ Wavelength of photon $\lambda=\frac{\mathrm{c}}{\mathrm{v}}$ $=\frac{3 \times 10^8}{6 \times 10^{14}}=0.5 \times 10^{-6}=500 \times 10^{-9}=500 \mathrm{~nm}$

Hence, the correct answer is option: 'B'.

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