Q90 / 180 · COMEDK 2015 · Mathematics

If $f(x+y)=f(x) f(y)$ for all $x$ and $y$ and $f(5)=2, f^{\prime}(0)=3$, then $f^{\prime}(5)$ is

  • A
    5
  • Correct answer
    B
    6
  • C
    0
  • D
    None of these

Solution

We have, $f(x+y)=f(x) f(y)$ Putting $x=y=0$ $$ \begin{array}{ll} \Rightarrow & f(0+0)=f(0) f(0) \\ \Rightarrow & f(0)=[f(0)]^{2} \\ \Rightarrow & f(0)=1 \\ \text { Now, } f^{\prime}(5)=\lim _{h \rightarrow 0} \frac{f(5+h)-f(5)}{h} \\ = & \lim _{h \rightarrow 0} \frac{f(5)}{f(h)-f(5)}=\lim _{h \rightarrow 0} f(5)\left[\frac{f(h)-1}{h}\right] \\ = & f(5) \lim _{h \rightarrow 0}\left[\frac{f(h)-f(0)}{h}\right]\quad \text{f(0)=1} \\ = & 2 \times f^{\prime}(0)=2 \times 3=6 \end{array} $$

Hence, the correct answer is option: 'B'.

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