Q115 / 155 · WBJEE 2021 · Mathematics
If $|z+i|-|z-1|=|z|-2=0$ for a complex number $z$, then $z=$
- A$\sqrt{2}(1+i)$
- Correct answerB$\sqrt{2}(1-i)$
- Correct answerC$\sqrt{2}(-1+i)$
- D$\sqrt{2}(-1-\mathrm{i})$
Solution
$|z| =2$ represents circle

$|z+i|=|z-1|$ represents
Solving $x^{2}+y^{2}=4$ and $y=-x$
$z=\sqrt{2}(1-i), \quad \sqrt{2}(-1+i)$

$|z+i|=|z-1|$ represents

Solving $x^{2}+y^{2}=4$ and $y=-x$

$z=\sqrt{2}(1-i), \quad \sqrt{2}(-1+i)$
Hence, the correct answer is options: 'B', 'C'.