If fx=√(x-4x-4)+tan^(-1)(1-2x)/(2+x), ∀4

Question

If fx=√(x-4x-4)+tan^(-1)(1-2x)/(2+x), ∀4<x<8, then the value of f^(′) 5 is equal to

MARKS Content Team · Accepted Answer

Correct answer: (A) -7/13. fx=√(x-4^2+2^2-2.2x-4)+tan^(-1)1/2-x1+1/2.x fx=√(x-4-2^2)+tan^(-1)1/2-tan^(-1)x fx=2-√(x-4)+tan^(-1)1/2-tan^(-1)x∵√(x-4)<2 f^(′) x =(−1)/(2√(x−4)) −1/(1+x^2) f^(′) 5 =(−1)/2 −1/(1+25) =(−14)/26 =−7/13

If $f (x) = \sqrt{x - 4 \sqrt{x - 4}} + t a n^{- 1} (\frac{1 - 2 x}{2 + x}), \forall 4 < x < 8,$ then the value of $f^{'} (5)$ is equal to

Solution

More Differentiation Questions

If fx=x-4x-4+tan-11-2x2+x, ∀4<x<8, then the value of f ′ 5 is equal to

Solution

More Differentiation Questions

If $f (x) = \sqrt{x - 4 \sqrt{x - 4}} + t a n^{- 1} (\frac{1 - 2 x}{2 + x}), \forall 4 < x < 8,$ then the value of $f^{'} (5)$ is equal to