If f(x)=cos^(-1)sinx4cos^2x-1, then 1/(π)f^(')(π)/3⋅f(π)/10 is

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MARKS Content Team · Accepted Answer

Correct answer: 0.60. fx=cos^(-1)sin⁡x41-sin^2x-1 fx=cos^(-1)sin⁡x3-4sin^2x=cos^(-1)3sin⁡x-4sin^3x fx=cos^(-1)sin⁡3x=(π)/2-sin^(-1)sin⁡3x In the neighbourhood of x=(π)/3⇒fx=(π)/2-π-3x fx=3x-(π)/2 ∴f^(')(π)/3=3 In the neighbourhood of x=(π)/10⇒fx=(π)/2-3x f(π)/10=(π)/2-(3π)/10=(π)/5

If $f (x) = c o s^{- 1} (s i n x (4 c o s^{2} x - 1))$ , then $\frac{1}{π} f^{'} (\frac{π}{3}) \cdot f (\frac{π}{10})$ is

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More Differentiation Questions

If f(x)=cos-1sinx4cos2x-1, then 1πf'π3⋅fπ10 is

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More Differentiation Questions

If $f (x) = c o s^{- 1} (s i n x (4 c o s^{2} x - 1))$ , then $\frac{1}{π} f^{'} (\frac{π}{3}) \cdot f (\frac{π}{10})$ is