Q95 / 180 · KCET 2015 · Mathematics
If \( f(x)=2 x^{2} \), find \( \frac{f(3.8)-f(4)}{3.8-4} \)
- A\( 1.56 \)
- B\( 156 \)
- Correct answerC\( 15.6 \)
- D\( 0.156 \)
Solution
Given that, \( f(x)=2 x^{2} \)
So, \( \frac{f(3.8)-f(4)}{3.8-4} \)
\( =\frac{2(3.8)^{2}-2(4)^{2}}{3.8-4}=\frac{2(3.8-4)(3.8+4)}{(3.8-4)} \)
\( =2(3.8+4)=15.6 \)
So, \( \frac{f(3.8)-f(4)}{3.8-4} \)
\( =\frac{2(3.8)^{2}-2(4)^{2}}{3.8-4}=\frac{2(3.8-4)(3.8+4)}{(3.8-4)} \)
\( =2(3.8+4)=15.6 \)
Hence, the correct answer is option: 'C'.