If $e$ is the electronic charge, $c$ is the speed of light in free space and $h$ is Planck's constant, the quantity $\frac{1}{4\pi {\epsilon }_0}\frac{{\left|\mathrm{e}\right|}^2}{hc}$ has dimensions of :

• A

  $\left[{\mathrm{MLT}}^0\right]$
• Correct answer
  B

  $\left[{\mathrm{M}}^0 {\mathrm{L}}^0 {\mathrm{T}}^0\right]$
• C

  $\left[{\mathrm{MLT}}^{-1}\right]$
• D

  $\left[{\mathrm{LC}}^{-1}\right]$

Hence, the correct answer is option: 'B'.