If $e_1$ and $e_2$ are the eccentricities of a hyperbola $3x^2-3y^2=25$ and its conjugate, then

• A

  $e_1^2+e_2^2=2$
• Correct answer
  B

  $e_1^2+e_2^2=4$
• C

  $e_1+e_2=4$
• D

  $e_1+e_2=\sqrt{2}$

Hence, the correct answer is option: 'B'.