Q124 / 150 · MHT CET 2009 · Physics

If dielectric is inserted in charged capacitor (battery removed), then quantity that remains constant is

A
capacitance
B
potential
C
intensity
Correct answer
D
charge

Solution

Variation of different variables (Q, $C, V, E$ and $U$ ) of parallel plate capacitor when dielectric $(K)$ is introduced when battery is removed is $$ \begin{array}{ll} C^{\prime}=K C & E^{\prime}=E / K \\ Q^{\prime}=Q & U^{\prime}=U / K \\ V^{\prime}=V / K & \end{array} $$

Hence, the correct answer is option: 'D'.

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